Charlie had 6 times as many stickers as Jenson at first. Then each of them bought an equal number of new stickers. In the end, Jenson had 60 stickers and Charlie had 3 times as many stickers as Jenson. How many stickers did both of them buy altogether?
| |
Charlie |
Jenson |
Difference |
| Before |
6x2 =
12 u |
1x2 =
2 u |
5x2 =
10 u |
| Change |
+ ? |
+ ? |
|
| After |
3x5 =
15 u |
1x5 =
5 u |
2x5 =
10 u |
The difference in the number of stickers at first and in the end remains unchanged. Make the difference in the number of stickers at first and in the end the same. LCM of 5 and 2 is 10.
Number of stickers that Jenson had in the end = 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Number of stickers that Charlie bought
= 15 u - 12 u
= 3 u
Number of stickers that both of them bought altogether
= 2 x 3 u
= 6 u
= 6 x 12
= 72
Answer(s): 72
