Sean had 6 times as many marbles as Will at first. Then each of them bought an equal number of new marbles. In the end, Will had 35 marbles and Sean had 3 times as many marbles as Will. How many marbles did both of them buy altogether?
| |
Sean |
Will |
Difference |
| Before |
6x2 =
12 u |
1x2 =
2 u |
5x2 =
10 u |
| Change |
+ ? |
+ ? |
|
| After |
3x5 =
15 u |
1x5 =
5 u |
2x5 =
10 u |
The difference in the number of marbles at first and in the end remains unchanged. Make the difference in the number of marbles at first and in the end the same. LCM of 5 and 2 is 10.
Number of marbles that Will had in the end = 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of marbles that Sean bought
= 15 u - 12 u
= 3 u
Number of marbles that both of them bought altogether
= 2 x 3 u
= 6 u
= 6 x 7
= 42
Answer(s): 42
