Lee had 5 times as many stickers as Albert at first. Then each of them bought an equal number of new stickers. In the end, Albert had 44 stickers and Lee had 4 times as many stickers as Albert. How many stickers did both of them buy altogether?
| |
Lee |
Albert |
Difference |
| Before |
5x3 =
15 u |
1x3 =
3 u |
4x3 =
12 u |
| Change |
+ ? |
+ ? |
|
| After |
4x4 =
16 u |
1x4 =
4 u |
3x4 =
12 u |
The difference in the number of stickers at first and in the end remains unchanged. Make the difference in the number of stickers at first and in the end the same. LCM of 4 and 3 is 12.
Number of stickers that Albert had in the end = 4 u
4 u = 44
1 u = 44 ÷ 4 = 11
Number of stickers that Lee bought
= 16 u - 15 u
= 1 u
Number of stickers that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 11
= 22
Answer(s): 22
