Rael had 5 times as many beads as Simon at first. Then each of them bought an equal number of new beads. In the end, Simon had 8 beads and Rael had 3 times as many beads as Simon. How many beads did both of them buy altogether?
| |
Rael |
Simon |
Difference |
| Before |
5x1 =
5 u |
1x1 =
1 u |
4x1 =
4 u |
| Change |
+ ? |
+ ? |
|
| After |
3x2 =
6 u |
1x2 =
2 u |
2x2 =
4 u |
The difference in the number of beads at first and in the end remains unchanged. Make the difference in the number of beads at first and in the end the same. LCM of 4 and 2 is 4.
Number of beads that Simon had in the end = 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Number of beads that Rael bought
= 6 u - 5 u
= 1 u
Number of beads that both of them bought altogether
= 2 x 1 u
= 2 u
= 2 x 4
= 8
Answer(s): 8
