Dylan and Pierre had $172 and $124 respectively. Each of them bought a jacket and a blouse at the same price. The cost of the jacket was 5 times as much as the blouse. In the end, Dylan had 4 times as much money as Pierre. What was the difference between the cost of the blouse and the jacket?

	Dylan	Pierre	Difference
Before	$172	$124	$48
Change	- 6 p	- 6 p
After	4 u	1 u	3 u

Since Dylan and Pierre bought the same items at the same price, the difference in the amounts they had remains unchanged at first and in the end.

4 u - 1 u = 172 - 124
3 u = 48

1 u = 48 ÷ 3 = 16

Cost of 1 jacket = 5 p
Cost of 1 blouse = 1 p

Total cost of 1 jacket and 1 blouse
= 5 p + 1 p
= 6 p

6 p = 124 - 16
6 p = 108

1 p = 108 ÷ 6 = 18

Difference in the cost between the jacket and the blouse
= 5 p - 1 p
= 4 p
= 4 x 18
= $72

Answer(s): $72