When Mr Brandon is 28 years old, his daughter is 6 years old. In how many years will he be 3 times as old as his daughter?
| |
Mr Brandon |
His daughter |
Difference |
| Before |
28 |
6 |
22 |
| Change |
+ ? |
+ ? |
|
| After |
3 u |
1 u |
2 u |
The difference in the age between Mr Brandon and his daughter at first and in the end remains the same.
Difference in the age between Mr Brandon and his daughter
= 3 u - 1 u
= 2 u
2 u = 28 - 6
2 u = 22
1 u = 22 ÷ 2 = 11
Number of years' time so Mr Brandon will be 3 times as old as his daughter
= 11 - 6
= 5
Answer(s): 5
