Paul is 6 years old. His mother is 33 years older than him. In how many years will Paul's mother be 4 times as old as Paul?
| |
His mother |
Paul |
Difference |
| Before |
39 |
6 |
33 |
| Change |
+ ? |
+ ? |
|
| After |
4 u |
1 u |
3 u |
The difference in the age between Paul and his mother at first and in the end remains the same.
Difference in the age between Paul and his mother
= 4 u - 1 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
The increase in age of Paul and his mother remains the same.
Number of years' time so Paul's mother will be 4 times as old as Paul
= 11 - 6
= 5
Answer(s): 5
