Mr Xavier is 2 times as old as his son, Oliver. 16 years ago, the ratio in the age of Mr Xavier and Oliver was 8 : 3. Find Oliver's current age.
| |
Mr Xavier |
Oliver |
Difference |
| Before |
8x1 =
8 u |
3x1 =
3 u |
5x1 =
5 u |
| Change |
+ 16 |
+ 16 |
|
| After |
2x5 =
10 u |
1x5 =
5 u |
1x5 =
5 u |
The difference in the age of Mr Xavier and Oliver at first and in the end remains unchanged. Make the difference in age the same. LCM of 5 and 1 is 5.
The increase in the age of Mr Xavier and Oliver is the same.
Increase in Oliver's age
= 5 u - 3 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Oliver's current age
= 5 u
= 5 x 8
= 40
Answer(s): 40
