Mr Howard is 2 times as old as his son, Jenson. 32 years ago, the ratio in the age of Mr Howard and Jenson was 10 : 3. Find Jenson's current age.
|
Mr Howard |
Jenson |
Difference |
Before |
10x1 = 10 u |
3x1 = 3 u |
7x1 = 7 u |
Change |
+ 32 |
+ 32 |
|
After |
2x7 = 14 u |
1x7 = 7 u |
1x7 = 7 u |
The difference in the age of Mr Howard and Jenson at first and in the end remains unchanged. Make the difference in age the same. LCM of 7 and 1 is 7.
The increase in the age of Mr Howard and Jenson is the same.
Increase in Jenson's age
= 7 u - 3 u
= 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
Jenson's current age
= 7 u
= 7 x 8
= 56
Answer(s): 56