Mr Albert is 2 times as old as his son, Neave. 15 years ago, the ratio in the age of Mr Albert and Neave was 7 : 2. Find Mr Albert's current age.
| |
Mr Albert |
Neave |
Difference |
| Before |
7x1 =
7 u |
2x1 =
2 u |
5x1 =
5 u |
| Change |
+ 15 |
+ 15 |
|
| After |
2x5 =
10 u |
1x5 =
5 u |
1x5 =
5 u |
The difference in the age of Mr Albert and Neave at first and in the end remains unchanged. Make the difference in age the same. LCM of 5 and 1 is 5.
The increase in the age of Mr Albert and Neave is the same.
Increase in Neave's age
= 5 u - 2 u
= 3 u
3 u = 15
1 u = 15 ÷ 3 = 5
Mr Albert's current age
= 10 u
= 10 x 5
= 50
Answer(s): 50
