Mr Harry is 2 times as old as his cousin, Simon. 32 years ago, the ratio in the age of Mr Harry and Simon was 10 : 3. Find Simon's current age.
|
Mr Harry |
Simon |
Difference |
Before |
10x1 = 10 u |
3x1 = 3 u |
7x1 = 7 u |
Change |
+ 32 |
+ 32 |
|
After |
2x7 = 14 u |
1x7 = 7 u |
1x7 = 7 u |
The difference in the age of Mr Harry and Simon at first and in the end remains unchanged. Make the difference in age the same. LCM of 7 and 1 is 7.
The increase in the age of Mr Harry and Simon is the same.
Increase in Simon's age
= 7 u - 3 u
= 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
Simon's current age
= 7 u
= 7 x 8
= 56
Answer(s): 56