Mr Simon is 2 times as old as his son, Jenson. 18 years ago, the ratio in the age of Mr Simon and Jenson was 7 : 2. Find Jenson's current age.
| |
Mr Simon |
Jenson |
Difference |
| Before |
7x1 =
7 u |
2x1 =
2 u |
5x1 =
5 u |
| Change |
+ 18 |
+ 18 |
|
| After |
2x5 =
10 u |
1x5 =
5 u |
1x5 =
5 u |
The difference in the age of Mr Simon and Jenson at first and in the end remains unchanged. Make the difference in age the same. LCM of 5 and 1 is 5.
The increase in the age of Mr Simon and Jenson is the same.
Increase in Jenson's age
= 5 u - 2 u
= 3 u
3 u = 18
1 u = 18 ÷ 3 = 6
Jenson's current age
= 5 u
= 5 x 6
= 30
Answer(s): 30
