Last week, Ken had a total of 158 black and green markers. Two weeks later, he sold
45 of all the black markers and bought another 16 green markers. Now he has the same number of black and green markers. How many markers does he have in the end?
| |
Black |
Green |
Total |
| Before |
5 u |
1 u - 16 |
6 u - 16 |
| Change |
- 4 u |
+ 16 |
|
| After |
1 u |
1 u |
|
Comparing the black
and green markers in the end |
1 |
1 |
|
Total number of markers at first
= 5 u + 1 u - 16
= 6 u - 16
6 u - 16 = 158
6 u = 158 + 16
6 u = 174
1 u = 174 ÷ 6 = 29
Number of markers that he has in the end
= 1 u + 1 u
= 2 u
= 2 x 29
= 58
Answer(s): 58
