Last week, Xavier had a total of 206 red and silver notebooks. Two weeks later, he sold
34 of all the red notebooks and bought another 29 silver notebooks. Now he has the same number of red and silver notebooks. How many notebooks does he have in the end?
| |
Red |
Silver |
Total |
| Before |
4 u |
1 u - 29 |
5 u - 29 |
| Change |
- 3 u |
+ 29 |
|
| After |
1 u |
1 u |
|
Comparing the red
and silver notebooks in the end |
1 |
1 |
|
Total number of notebooks at first
= 4 u + 1 u - 29
= 5 u - 29
5 u - 29 = 206
5 u = 206 + 29
5 u = 235
1 u = 235 ÷ 5 = 47
Number of notebooks that he has in the end
= 1 u + 1 u
= 2 u
= 2 x 47
= 94
Answer(s): 94
