A fruit seller sells only mangoes and starfruits. The ratio of mangoes to starfruits is 1 : 2. A total of 51 fruits are added. The number of mangoes becomes 2 times as many as before and the number of starfruits becomes 2 times as many as before. How many fruits are there in the end?
|
Comparing mangoes at first and in the end |
Mangoes |
Starfruits |
Comparing starfruits at first and in the end |
Before |
1x1 = 1 u |
1 u |
2 u |
1x2 = 2 u |
Change |
|
+ 51 |
|
After |
2x1 = 2 u |
2 u |
4 u |
2x2 = 4 u |
The number of starfruits at first is repeated. Make the number of starfruits at first the same. LCM of 1 and 2 is 2.
The number of mangoes at first is repeated. Make the number of mangoes at first the same. LCM of 1 and 1 is 1.
Number of fruits at first
= 1 u + 2 u
= 3 u
Number of fruits in the end
= 2 u + 4 u
= 6 u
Number of fruits added
= 6 u - 3 u
= 3 u
3 u = 51
1 u = 51 ÷ 3 = 17
Number of fruits in the end
= 6 u
= 6 x 17
= 102
Answer(s): 102