A fruit seller sells only kiwis and mangosteens. The ratio of kiwis to mangosteens is 2 : 5. A total of 77 fruits are added. The number of kiwis becomes 2 times as many as before and the number of mangosteens becomes 2 times as many as before. How many fruits are there in the end?
|
Comparing kiwis at first and in the end |
Kiwis |
Mangosteens |
Comparing mangosteens at first and in the end |
Before |
1x2 = 2 u |
2 u |
5 u |
1x5 = 5 u |
Change |
|
+ 77 |
|
After |
2x2 = 4 u |
4 u |
10 u |
2x5 = 10 u |
The number of mangosteens at first is repeated. Make the number of mangosteens at first the same. LCM of 1 and 5 is 5.
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 2 is 2.
Number of fruits at first
= 2 u + 5 u
= 7 u
Number of fruits in the end
= 4 u + 10 u
= 14 u
Number of fruits added
= 14 u - 7 u
= 7 u
7 u = 77
1 u = 77 ÷ 7 = 11
Number of fruits in the end
= 14 u
= 14 x 11
= 154
Answer(s): 154