A fruit seller sells only starfruits and peaches. The ratio of starfruits to peaches is 3 : 5. A total of 143 fruits are added. The number of starfruits becomes 3 times as many as before and the number of peaches becomes 2 times as many as before. How many fruits are there at first?
|
Comparing starfruits at first and in the end |
Starfruits |
Peaches |
Comparing peaches at first and in the end |
Before |
1x3 = 3 u |
3 u |
5 u |
1x5 = 5 u |
Change |
|
+ 143 |
|
After |
3x3 = 9 u |
9 u |
10 u |
2x5 = 10 u |
The number of peaches at first is repeated. Make the number of peaches at first the same. LCM of 1 and 5 is 5.
The number of starfruits at first is repeated. Make the number of starfruits at first the same. LCM of 1 and 3 is 3.
Number of fruits at first
= 3 u + 5 u
= 8 u
Number of fruits in the end
= 9 u + 10 u
= 19 u
Number of fruits added
= 19 u - 8 u
= 11 u
11 u = 143
1 u = 143 ÷ 11 = 13
Number of fruits at first
= 8 u
= 8 x 13
= 104
Answer(s): 104