A fruit seller sells only kiwis and peaches. The ratio of kiwis to peaches is 3 : 5. A total of 39 fruits are added. The number of kiwis becomes 2 times as many as before and the number of peaches becomes 3 times as many as before. How many fruits are there at first?
|
Comparing kiwis at first and in the end |
Kiwis |
Peaches |
Comparing peaches at first and in the end |
Before |
1x3 = 3 u |
3 u |
5 u |
1x5 = 5 u |
Change |
|
+ 39 |
|
After |
2x3 = 6 u |
6 u |
15 u |
3x5 = 15 u |
The number of peaches at first is repeated. Make the number of peaches at first the same. LCM of 1 and 5 is 5.
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 3 is 3.
Number of fruits at first
= 3 u + 5 u
= 8 u
Number of fruits in the end
= 6 u + 15 u
= 21 u
Number of fruits added
= 21 u - 8 u
= 13 u
13 u = 39
1 u = 39 ÷ 13 = 3
Number of fruits at first
= 8 u
= 8 x 3
= 24
Answer(s): 24