A fruit seller sells only chikoos and kiwis. The ratio of chikoos to kiwis is 3 : 5. A total of 189 fruits are added. The number of chikoos becomes 3 times as many as before and the number of kiwis becomes 4 times as many as before. How many fruits are there in the end?
|
Comparing chikoos at first and in the end |
Chikoos |
Kiwis |
Comparing kiwis at first and in the end |
Before |
1x3 = 3 u |
3 u |
5 u |
1x5 = 5 u |
Change |
|
+ 189 |
|
After |
3x3 = 9 u |
9 u |
20 u |
4x5 = 20 u |
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 5 is 5.
The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 1 and 3 is 3.
Number of fruits at first
= 3 u + 5 u
= 8 u
Number of fruits in the end
= 9 u + 20 u
= 29 u
Number of fruits added
= 29 u - 8 u
= 21 u
21 u = 189
1 u = 189 ÷ 21 = 9
Number of fruits in the end
= 29 u
= 29 x 9
= 261
Answer(s): 261