A fruit seller sells only kiwis and pomegranates. The ratio of kiwis to pomegranates is 1 : 2. A total of 99 fruits are added. The number of kiwis becomes 4 times as many as before and the number of pomegranates becomes 4 times as many as before. How many fruits are there in the end?
|
Comparing kiwis at first and in the end |
Kiwis |
Pomegranates |
Comparing pomegranates at first and in the end |
Before |
1x1 = 1 u |
1 u |
2 u |
1x2 = 2 u |
Change |
|
+ 99 |
|
After |
4x1 = 4 u |
4 u |
8 u |
4x2 = 8 u |
The number of pomegranates at first is repeated. Make the number of pomegranates at first the same. LCM of 1 and 2 is 2.
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 1 is 1.
Number of fruits at first
= 1 u + 2 u
= 3 u
Number of fruits in the end
= 4 u + 8 u
= 12 u
Number of fruits added
= 12 u - 3 u
= 9 u
9 u = 99
1 u = 99 ÷ 9 = 11
Number of fruits in the end
= 12 u
= 12 x 11
= 132
Answer(s): 132