A fruit seller sells only guavas and pomegranates. The ratio of guavas to pomegranates is 3 : 5. A total of 136 fruits are added. The number of guavas becomes 2 times as many as before and the number of pomegranates becomes 2 times as many as before. How many fruits are there in the end?

	Comparing guavas at first and in the end	Guavas	Pomegranates	Comparing pomegranates at first and in the end
Before	1x3 = 3 u	3 u	5 u	1x5 = 5 u
Change		+ 136
After	2x3 = 6 u	6 u	10 u	2x5 = 10 u

The number of pomegranates at first is repeated.  Make the number of pomegranates at first the same.  LCM of 1 and 5 is 5.

The number of guavas at first is repeated. Make the number of guavas at first the same. LCM of 1 and 3 is 3.

Number of fruits at first
= 3 u + 5 u
= 8 u

Number of fruits in the end
= 6 u + 10 u
= 16 u

Number of fruits added
= 16 u - 8 u 
= 8 u

8 u = 136

1 u = 136 ÷ 8 = 17

Number of fruits in the end
= 16 u
= 16 x 17
= 272

Answer(s): 272