A fruit seller sells only starfruits and kiwis. The ratio of starfruits to kiwis is 2 : 5. A total of 361 fruits are added. The number of starfruits becomes 3 times as many as before and the number of kiwis becomes 4 times as many as before. How many fruits are there at first?
|
Comparing starfruits at first and in the end |
Starfruits |
Kiwis |
Comparing kiwis at first and in the end |
Before |
1x2 = 2 u |
2 u |
5 u |
1x5 = 5 u |
Change |
|
+ 361 |
|
After |
3x2 = 6 u |
6 u |
20 u |
4x5 = 20 u |
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 5 is 5.
The number of starfruits at first is repeated. Make the number of starfruits at first the same. LCM of 1 and 2 is 2.
Number of fruits at first
= 2 u + 5 u
= 7 u
Number of fruits in the end
= 6 u + 20 u
= 26 u
Number of fruits added
= 26 u - 7 u
= 19 u
19 u = 361
1 u = 361 ÷ 19 = 19
Number of fruits at first
= 7 u
= 7 x 19
= 133
Answer(s): 133