A fruit seller sells only guavas and chikoos. The ratio of guavas to chikoos is 2 : 3. A total of 60 fruits are added. The number of guavas becomes 3 times as many as before and the number of chikoos becomes 3 times as many as before. How many fruits are there at first?
|
Comparing guavas at first and in the end |
Guavas |
Chikoos |
Comparing chikoos at first and in the end |
Before |
1x2 = 2 u |
2 u |
3 u |
1x3 = 3 u |
Change |
|
+ 60 |
|
After |
3x2 = 6 u |
6 u |
9 u |
3x3 = 9 u |
The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 1 and 3 is 3.
The number of guavas at first is repeated. Make the number of guavas at first the same. LCM of 1 and 2 is 2.
Number of fruits at first
= 2 u + 3 u
= 5 u
Number of fruits in the end
= 6 u + 9 u
= 15 u
Number of fruits added
= 15 u - 5 u
= 10 u
10 u = 60
1 u = 60 ÷ 10 = 6
Number of fruits at first
= 5 u
= 5 x 6
= 30
Answer(s): 30