A fruit seller sells only chikoos and persimmons. The ratio of chikoos to persimmons is 2 : 3. A total of 44 fruits are added. The number of chikoos becomes 2 times as many as before and the number of persimmons becomes 4 times as many as before. How many fruits are there in the end?

	Comparing chikoos at first and in the end	Chikoos	Persimmons	Comparing persimmons at first and in the end
Before	1x2 = 2 u	2 u	3 u	1x3 = 3 u
Change		+ 44
After	2x2 = 4 u	4 u	12 u	4x3 = 12 u

The number of persimmons at first is repeated.  Make the number of persimmons at first the same.  LCM of 1 and 3 is 3.

The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 1 and 2 is 2.

Number of fruits at first
= 2 u + 3 u
= 5 u

Number of fruits in the end
= 4 u + 12 u
= 16 u

Number of fruits added
= 16 u - 5 u 
= 11 u

11 u = 44

1 u = 44 ÷ 11 = 4

Number of fruits in the end
= 16 u
= 16 x 4
= 64

Answer(s): 64