A fruit seller sells only pomegranates and dragonfruits. The ratio of pomegranates to dragonfruits is 3 : 5. A total of 380 fruits are added. The number of pomegranates becomes 4 times as many as before and the number of dragonfruits becomes 3 times as many as before. How many fruits are there at first?
|
Comparing pomegranates at first and in the end |
Pomegranates |
Dragonfruits |
Comparing dragonfruits at first and in the end |
Before |
1x3 = 3 u |
3 u |
5 u |
1x5 = 5 u |
Change |
|
+ 380 |
|
After |
4x3 = 12 u |
12 u |
15 u |
3x5 = 15 u |
The number of dragonfruits at first is repeated. Make the number of dragonfruits at first the same. LCM of 1 and 5 is 5.
The number of pomegranates at first is repeated. Make the number of pomegranates at first the same. LCM of 1 and 3 is 3.
Number of fruits at first
= 3 u + 5 u
= 8 u
Number of fruits in the end
= 12 u + 15 u
= 27 u
Number of fruits added
= 27 u - 8 u
= 19 u
19 u = 380
1 u = 380 ÷ 19 = 20
Number of fruits at first
= 8 u
= 8 x 20
= 160
Answer(s): 160