A fruit seller sells only kiwis and pears. The ratio of kiwis to pears is 1 : 3. A total of 135 fruits are added. The number of kiwis becomes 4 times as many as before and the number of pears becomes 3 times as many as before. How many fruits are there in the end?
|
Comparing kiwis at first and in the end |
Kiwis |
Pears |
Comparing pears at first and in the end |
Before |
1x1 = 1 u |
1 u |
3 u |
1x3 = 3 u |
Change |
|
+ 135 |
|
After |
4x1 = 4 u |
4 u |
9 u |
3x3 = 9 u |
The number of pears at first is repeated. Make the number of pears at first the same. LCM of 1 and 3 is 3.
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 1 is 1.
Number of fruits at first
= 1 u + 3 u
= 4 u
Number of fruits in the end
= 4 u + 9 u
= 13 u
Number of fruits added
= 13 u - 4 u
= 9 u
9 u = 135
1 u = 135 ÷ 9 = 15
Number of fruits in the end
= 13 u
= 13 x 15
= 195
Answer(s): 195