A fruit seller sells only dragonfruits and chikoos. The ratio of dragonfruits to chikoos is 4 : 5. A total of 340 fruits are added. The number of dragonfruits becomes 4 times as many as before and the number of chikoos becomes 2 times as many as before. How many fruits are there at first?
|
Comparing dragonfruits at first and in the end |
Dragonfruits |
Chikoos |
Comparing chikoos at first and in the end |
Before |
1x4 = 4 u |
4 u |
5 u |
1x5 = 5 u |
Change |
|
+ 340 |
|
After |
4x4 = 16 u |
16 u |
10 u |
2x5 = 10 u |
The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 1 and 5 is 5.
The number of dragonfruits at first is repeated. Make the number of dragonfruits at first the same. LCM of 1 and 4 is 4.
Number of fruits at first
= 4 u + 5 u
= 9 u
Number of fruits in the end
= 16 u + 10 u
= 26 u
Number of fruits added
= 26 u - 9 u
= 17 u
17 u = 340
1 u = 340 ÷ 17 = 20
Number of fruits at first
= 9 u
= 9 x 20
= 180
Answer(s): 180