A fruit seller sells only chikoos and dragonfruits. The ratio of chikoos to dragonfruits is 1 : 3. A total of 228 fruits are added. The number of chikoos becomes 4 times as many as before and the number of dragonfruits becomes 4 times as many as before. How many fruits are there in the end?
|
Comparing chikoos at first and in the end |
Chikoos |
Dragonfruits |
Comparing dragonfruits at first and in the end |
Before |
1x1 = 1 u |
1 u |
3 u |
1x3 = 3 u |
Change |
|
+ 228 |
|
After |
4x1 = 4 u |
4 u |
12 u |
4x3 = 12 u |
The number of dragonfruits at first is repeated. Make the number of dragonfruits at first the same. LCM of 1 and 3 is 3.
The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 1 and 1 is 1.
Number of fruits at first
= 1 u + 3 u
= 4 u
Number of fruits in the end
= 4 u + 12 u
= 16 u
Number of fruits added
= 16 u - 4 u
= 12 u
12 u = 228
1 u = 228 ÷ 12 = 19
Number of fruits in the end
= 16 u
= 16 x 19
= 304
Answer(s): 304