A fruit seller sells only peaches and pears. The ratio of peaches to pears is 3 : 5. A total of 336 fruits are added. The number of peaches becomes 4 times as many as before and the number of pears becomes 4 times as many as before. How many fruits are there at first?
|
Comparing peaches at first and in the end |
Peaches |
Pears |
Comparing pears at first and in the end |
Before |
1x3 = 3 u |
3 u |
5 u |
1x5 = 5 u |
Change |
|
+ 336 |
|
After |
4x3 = 12 u |
12 u |
20 u |
4x5 = 20 u |
The number of pears at first is repeated. Make the number of pears at first the same. LCM of 1 and 5 is 5.
The number of peaches at first is repeated. Make the number of peaches at first the same. LCM of 1 and 3 is 3.
Number of fruits at first
= 3 u + 5 u
= 8 u
Number of fruits in the end
= 12 u + 20 u
= 32 u
Number of fruits added
= 32 u - 8 u
= 24 u
24 u = 336
1 u = 336 ÷ 24 = 14
Number of fruits at first
= 8 u
= 8 x 14
= 112
Answer(s): 112