A fruit seller sells only chikoos and pomegranates. The ratio of chikoos to pomegranates is 2 : 3. A total of 117 fruits are added. The number of chikoos becomes 4 times as many as before and the number of pomegranates becomes 2 times as many as before. How many fruits are there in the end?
|
Comparing chikoos at first and in the end |
Chikoos |
Pomegranates |
Comparing pomegranates at first and in the end |
Before |
1x2 = 2 u |
2 u |
3 u |
1x3 = 3 u |
Change |
|
+ 117 |
|
After |
4x2 = 8 u |
8 u |
6 u |
2x3 = 6 u |
The number of pomegranates at first is repeated. Make the number of pomegranates at first the same. LCM of 1 and 3 is 3.
The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 1 and 2 is 2.
Number of fruits at first
= 2 u + 3 u
= 5 u
Number of fruits in the end
= 8 u + 6 u
= 14 u
Number of fruits added
= 14 u - 5 u
= 9 u
9 u = 117
1 u = 117 ÷ 9 = 13
Number of fruits in the end
= 14 u
= 14 x 13
= 182
Answer(s): 182