A fruit seller sells only pears and lemons. The ratio of pears to lemons is 1 : 2. A total of 85 fruits are added. The number of pears becomes 2 times as many as before and the number of lemons becomes 3 times as many as before. How many fruits are there in the end?

	Comparing pears at first and in the end	Pears	Lemons	Comparing lemons at first and in the end
Before	1x1 = 1 u	1 u	2 u	1x2 = 2 u
Change		+ 85
After	2x1 = 2 u	2 u	6 u	3x2 = 6 u

The number of lemons at first is repeated.  Make the number of lemons at first the same.  LCM of 1 and 2 is 2.

The number of pears at first is repeated. Make the number of pears at first the same. LCM of 1 and 1 is 1.

Number of fruits at first
= 1 u + 2 u
= 3 u

Number of fruits in the end
= 2 u + 6 u
= 8 u

Number of fruits added
= 8 u - 3 u 
= 5 u

5 u = 85

1 u = 85 ÷ 5 = 17

Number of fruits in the end
= 8 u
= 8 x 17
= 136

Answer(s): 136