A fruit seller sells only guavas and persimmons. The ratio of guavas to persimmons is 2 : 5. A total of 154 fruits are added. The number of guavas becomes 4 times as many as before and the number of persimmons becomes 2 times as many as before. How many fruits are there at first?
|
Comparing guavas at first and in the end |
Guavas |
Persimmons |
Comparing persimmons at first and in the end |
Before |
1x2 = 2 u |
2 u |
5 u |
1x5 = 5 u |
Change |
|
+ 154 |
|
After |
4x2 = 8 u |
8 u |
10 u |
2x5 = 10 u |
The number of persimmons at first is repeated. Make the number of persimmons at first the same. LCM of 1 and 5 is 5.
The number of guavas at first is repeated. Make the number of guavas at first the same. LCM of 1 and 2 is 2.
Number of fruits at first
= 2 u + 5 u
= 7 u
Number of fruits in the end
= 8 u + 10 u
= 18 u
Number of fruits added
= 18 u - 7 u
= 11 u
11 u = 154
1 u = 154 ÷ 11 = 14
Number of fruits at first
= 7 u
= 7 x 14
= 98
Answer(s): 98