A fruit seller sells only dragonfruits and kiwis. The ratio of dragonfruits to kiwis is 2 : 3. A total of 120 fruits are added. The number of dragonfruits becomes 4 times as many as before and the number of kiwis becomes 3 times as many as before. How many fruits are there in the end?
|
Comparing dragonfruits at first and in the end |
Dragonfruits |
Kiwis |
Comparing kiwis at first and in the end |
Before |
1x2 = 2 u |
2 u |
3 u |
1x3 = 3 u |
Change |
|
+ 120 |
|
After |
4x2 = 8 u |
8 u |
9 u |
3x3 = 9 u |
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 3 is 3.
The number of dragonfruits at first is repeated. Make the number of dragonfruits at first the same. LCM of 1 and 2 is 2.
Number of fruits at first
= 2 u + 3 u
= 5 u
Number of fruits in the end
= 8 u + 9 u
= 17 u
Number of fruits added
= 17 u - 5 u
= 12 u
12 u = 120
1 u = 120 ÷ 12 = 10
Number of fruits in the end
= 17 u
= 17 x 10
= 170
Answer(s): 170