A fruit seller sells only pomegranates and guavas. The ratio of pomegranates to guavas is 2 : 5. A total of 171 fruits are added. The number of pomegranates becomes 3 times as many as before and the number of guavas becomes 2 times as many as before. How many fruits are there in the end?

	Comparing pomegranates at first and in the end	Pomegranates	Guavas	Comparing guavas at first and in the end
Before	1x2 = 2 u	2 u	5 u	1x5 = 5 u
Change		+ 171
After	3x2 = 6 u	6 u	10 u	2x5 = 10 u

The number of guavas at first is repeated.  Make the number of guavas at first the same.  LCM of 1 and 5 is 5.

The number of pomegranates at first is repeated. Make the number of pomegranates at first the same. LCM of 1 and 2 is 2.

Number of fruits at first
= 2 u + 5 u
= 7 u

Number of fruits in the end
= 6 u + 10 u
= 16 u

Number of fruits added
= 16 u - 7 u 
= 9 u

9 u = 171

1 u = 171 ÷ 9 = 19

Number of fruits in the end
= 16 u
= 16 x 19
= 304

Answer(s): 304