A fruit seller sells only starfruits and peaches. The ratio of starfruits to peaches is 1 : 3. A total of 108 fruits are added. The number of starfruits becomes 4 times as many as before and the number of peaches becomes 4 times as many as before. How many fruits are there in the end?
|
Comparing starfruits at first and in the end |
Starfruits |
Peaches |
Comparing peaches at first and in the end |
Before |
1x1 = 1 u |
1 u |
3 u |
1x3 = 3 u |
Change |
|
+ 108 |
|
After |
4x1 = 4 u |
4 u |
12 u |
4x3 = 12 u |
The number of peaches at first is repeated. Make the number of peaches at first the same. LCM of 1 and 3 is 3.
The number of starfruits at first is repeated. Make the number of starfruits at first the same. LCM of 1 and 1 is 1.
Number of fruits at first
= 1 u + 3 u
= 4 u
Number of fruits in the end
= 4 u + 12 u
= 16 u
Number of fruits added
= 16 u - 4 u
= 12 u
12 u = 108
1 u = 108 ÷ 12 = 9
Number of fruits in the end
= 16 u
= 16 x 9
= 144
Answer(s): 144