A fruit seller sells only pomegranates and kiwis. The ratio of pomegranates to kiwis is 3 : 4. A total of 117 fruits are added. The number of pomegranates becomes 4 times as many as before and the number of kiwis becomes 2 times as many as before. How many fruits are there in the end?
|
Comparing pomegranates at first and in the end |
Pomegranates |
Kiwis |
Comparing kiwis at first and in the end |
Before |
1x3 = 3 u |
3 u |
4 u |
1x4 = 4 u |
Change |
|
+ 117 |
|
After |
4x3 = 12 u |
12 u |
8 u |
2x4 = 8 u |
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 4 is 4.
The number of pomegranates at first is repeated. Make the number of pomegranates at first the same. LCM of 1 and 3 is 3.
Number of fruits at first
= 3 u + 4 u
= 7 u
Number of fruits in the end
= 12 u + 8 u
= 20 u
Number of fruits added
= 20 u - 7 u
= 13 u
13 u = 117
1 u = 117 ÷ 13 = 9
Number of fruits in the end
= 20 u
= 20 x 9
= 180
Answer(s): 180