A fruit seller sells only starfruits and guavas. The ratio of starfruits to guavas is 1 : 2. A total of 144 fruits are added. The number of starfruits becomes 3 times as many as before and the number of guavas becomes 4 times as many as before. How many fruits are there at first?
|
Comparing starfruits at first and in the end |
Starfruits |
Guavas |
Comparing guavas at first and in the end |
Before |
1x1 = 1 u |
1 u |
2 u |
1x2 = 2 u |
Change |
|
+ 144 |
|
After |
3x1 = 3 u |
3 u |
8 u |
4x2 = 8 u |
The number of guavas at first is repeated. Make the number of guavas at first the same. LCM of 1 and 2 is 2.
The number of starfruits at first is repeated. Make the number of starfruits at first the same. LCM of 1 and 1 is 1.
Number of fruits at first
= 1 u + 2 u
= 3 u
Number of fruits in the end
= 3 u + 8 u
= 11 u
Number of fruits added
= 11 u - 3 u
= 8 u
8 u = 144
1 u = 144 ÷ 8 = 18
Number of fruits at first
= 3 u
= 3 x 18
= 54
Answer(s): 54