A fruit seller sells only peaches and kiwis. The ratio of peaches to kiwis is 4 : 5. A total of 36 fruits are added. The number of peaches becomes 3 times as many as before and the number of kiwis becomes 3 times as many as before. How many fruits are there in the end?
|
Comparing peaches at first and in the end |
Peaches |
Kiwis |
Comparing kiwis at first and in the end |
Before |
1x4 = 4 u |
4 u |
5 u |
1x5 = 5 u |
Change |
|
+ 36 |
|
After |
3x4 = 12 u |
12 u |
15 u |
3x5 = 15 u |
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 5 is 5.
The number of peaches at first is repeated. Make the number of peaches at first the same. LCM of 1 and 4 is 4.
Number of fruits at first
= 4 u + 5 u
= 9 u
Number of fruits in the end
= 12 u + 15 u
= 27 u
Number of fruits added
= 27 u - 9 u
= 18 u
18 u = 36
1 u = 36 ÷ 18 = 2
Number of fruits in the end
= 27 u
= 27 x 2
= 54
Answer(s): 54