A fruit seller sells only mangoes and peaches. The ratio of mangoes to peaches is 1 : 2. A total of 114 fruits are added. The number of mangoes becomes 3 times as many as before and the number of peaches becomes 3 times as many as before. How many fruits are there at first?
|
Comparing mangoes at first and in the end |
Mangoes |
Peaches |
Comparing peaches at first and in the end |
Before |
1x1 = 1 u |
1 u |
2 u |
1x2 = 2 u |
Change |
|
+ 114 |
|
After |
3x1 = 3 u |
3 u |
6 u |
3x2 = 6 u |
The number of peaches at first is repeated. Make the number of peaches at first the same. LCM of 1 and 2 is 2.
The number of mangoes at first is repeated. Make the number of mangoes at first the same. LCM of 1 and 1 is 1.
Number of fruits at first
= 1 u + 2 u
= 3 u
Number of fruits in the end
= 3 u + 6 u
= 9 u
Number of fruits added
= 9 u - 3 u
= 6 u
6 u = 114
1 u = 114 ÷ 6 = 19
Number of fruits at first
= 3 u
= 3 x 19
= 57
Answer(s): 57