A fruit seller sells only kiwis and chikoos. The ratio of kiwis to chikoos is 2 : 5. A total of 110 fruits are added. The number of kiwis becomes 4 times as many as before and the number of chikoos becomes 2 times as many as before. How many fruits are there in the end?
|
Comparing kiwis at first and in the end |
Kiwis |
Chikoos |
Comparing chikoos at first and in the end |
Before |
1x2 = 2 u |
2 u |
5 u |
1x5 = 5 u |
Change |
|
+ 110 |
|
After |
4x2 = 8 u |
8 u |
10 u |
2x5 = 10 u |
The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 1 and 5 is 5.
The number of kiwis at first is repeated. Make the number of kiwis at first the same. LCM of 1 and 2 is 2.
Number of fruits at first
= 2 u + 5 u
= 7 u
Number of fruits in the end
= 8 u + 10 u
= 18 u
Number of fruits added
= 18 u - 7 u
= 11 u
11 u = 110
1 u = 110 ÷ 11 = 10
Number of fruits in the end
= 18 u
= 18 x 10
= 180
Answer(s): 180