The ratio of Tim's to Lee's money is 3 : 7. The ratio of Lee's to Xavier's money is 3 : 5. If Tim has $171, how much more does Xavier have than Lee?
Tim |
Lee |
Xavier |
3x3 |
7x3 |
|
|
3x7 |
5x7 |
9 u |
21 u |
35 u |
The amount that Lee has is the repeated identity.
Use LCM to make it the same.
LCM of 7 and 3 = 21
Amount that Tim has = 9 u
9 u = 171
1 u = 171 ÷ 9 = 19
Amount that Xavier has more than Lee
= 35 u - 21 u
= 14 u
= 14 x 19
= $266
Answer(s): $266