The ratio of Ken's to Xavier's money is 8 : 7. The ratio of Xavier's to Sean's money is 3 : 5. If Ken has $312, how much less does Xavier have than Sean?
Ken |
Xavier |
Sean |
8x3 |
7x3 |
|
|
3x7 |
5x7 |
24 u |
21 u |
35 u |
The amount that Xavier has is the repeated identity.
Use LCM to make it the same.
LCM of 7 and 3 = 21
Amount that Ken has = 24 u
24 u = 312
1 u = 312 ÷ 24 = 13
Amount that Xavier has less than Sean
= 35 u - 21 u
= 14 u
= 14 x 13
= $182
Answer(s): $182