There were blue, green and yellow marbles in a jar. Sean put another 6 blue marbles and 14 yellow marbles in the jar, then the ratio of the number of green marbles to the number of yellow marbles became 4 : 3. Then, he doubled the number of blue marbles and removed 27 yellow marbles. The ratio of the number of blue marbles to green marbles became 2 : 1. He counted and found that there were a total of 33 marbles left in the jar. Find the number of blue marbles that he had in the end.
|
Blue marbles |
Green marbles |
Yellow marbles |
Total |
Before |
4 u - 6 |
4 u |
3 u - 14 |
|
Change 1 |
+ 6 |
|
+ 14 |
|
After 1
|
1x4 = 4 u |
4 u |
3 u |
|
Change 2
|
+ 1x4 = 4 u |
|
- 27 |
|
After 2
|
2x4 = 8 u |
1x4 = 4 u |
3 u - 27 |
33 |
The number of green marbles remains unchanged. Make the number of green marbles the same. LCM of 1 and 4 is 4.
Total number of marbles in the end
= 8 u + 4 u + 3 u - 27
= 15 u - 27
15 u - 27 = 33
15 u = 33 + 27
15 u = 60
1 u = 60 ÷ 15 = 4
Number of blue marbles in the end
= 8 u
= 8 x 4
= 32
Answer(s): 32