There were brown, purple and white marbles in a container. Sean put another 5 brown marbles and 4 white marbles in the container, then the ratio of the number of purple marbles to the number of white marbles became 5 : 3. Then, he doubled the number of brown marbles and removed 27 white marbles. The ratio of the number of brown marbles to purple marbles became 2 : 1. He counted and found that there were a total of 27 marbles left in the container. Find the number of brown marbles that he had at first.
|
Brown marbles |
Purple marbles |
White marbles |
Total |
Before |
5 u - 5 |
5 u |
3 u - 4 |
|
Change 1 |
+ 5 |
|
+ 4 |
|
After 1
|
1x5 = 5 u |
5 u |
3 u |
|
Change 2
|
+ 1x5 = 5 u |
|
- 27 |
|
After 2
|
2x5 = 10 u |
1x5 = 5 u |
3 u - 27 |
27 |
The number of purple marbles remains unchanged. Make the number of purple marbles the same. LCM of 1 and 5 is 5.
Total number of marbles in the end
= 10 u + 5 u + 3 u - 27
= 18 u - 27
18 u - 27 = 27
18 u = 27 + 27
18 u = 54
1 u = 54 ÷ 18 = 3
Number of brown marbles at first
= 5 u - 5
= 5 x 3 - 5
= 15 - 5
= 10
Answer(s): 10