There were red, blue and brown beads in a container. Sean put another 3 red beads and 15 brown beads in the container, then the ratio of the number of blue beads to the number of brown beads became 4 : 3. Then, he doubled the number of red beads and removed 17 brown beads. The ratio of the number of red beads to blue beads became 2 : 1. He counted and found that there were a total of 88 beads left in the container. Find the number of red beads that he had in the end.

	Red beads	Blue beads	Brown beads	Total
Before	4 u - 3	4 u	3 u - 15
Change 1	+ 3		+ 15
After 1	1x4 = 4 u	4 u	3 u
Change 2	+ 1x4 = 4 u		- 17
After 2	2x4 = 8 u	1x4 = 4 u	3 u - 17	88

The number of blue beads remains unchanged. Make the number of blue beads the same. LCM of 1 and 4 is 4.

Total number of beads in the end
= 8 u + 4 u + 3 u - 17
= 15 u - 17

15 u - 17 = 88
15 u = 88 + 17
15 u = 105

1 u = 105 ÷ 15 = 7

Number of red beads in the end
= 8 u 
= 8 x 7
= 56

Answer(s): 56