There were yellow, brown and purple beads in a jar. Sean put another 8 yellow beads and 15 purple beads in the jar, then the ratio of the number of brown beads to the number of purple beads became 5 : 2. Then, he doubled the number of yellow beads and removed 11 purple beads. The ratio of the number of yellow beads to brown beads became 2 : 1. He counted and found that there were a total of 57 beads left in the jar. Find the number of yellow beads that he had at first.
|
Yellow beads |
Brown beads |
Purple beads |
Total |
Before |
5 u - 8 |
5 u |
2 u - 15 |
|
Change 1 |
+ 8 |
|
+ 15 |
|
After 1
|
1x5 = 5 u |
5 u |
2 u |
|
Change 2
|
+ 1x5 = 5 u |
|
- 11 |
|
After 2
|
2x5 = 10 u |
1x5 = 5 u |
2 u - 11 |
57 |
The number of brown beads remains unchanged. Make the number of brown beads the same. LCM of 1 and 5 is 5.
Total number of beads in the end
= 10 u + 5 u + 2 u - 11
= 17 u - 11
17 u - 11 = 57
17 u = 57 + 11
17 u = 68
1 u = 68 ÷ 17 = 4
Number of yellow beads at first
= 5 u - 8
= 5 x 4 - 8
= 20 - 8
= 12
Answer(s): 12