There were green, white and pink balls in a container. Sean put another 9 green balls and 13 pink balls in the container, then the ratio of the number of white balls to the number of pink balls became 4 : 3. Then, he doubled the number of green balls and removed 13 pink balls. The ratio of the number of green balls to white balls became 2 : 1. He counted and found that there were a total of 32 balls left in the container. Find the number of green balls that he had in the end.

	Green balls	White balls	Pink balls	Total
Before	4 u - 9	4 u	3 u - 13
Change 1	+ 9		+ 13
After 1	1x4 = 4 u	4 u	3 u
Change 2	+ 1x4 = 4 u		- 13
After 2	2x4 = 8 u	1x4 = 4 u	3 u - 13	32

The number of white balls remains unchanged. Make the number of white balls the same. LCM of 1 and 4 is 4.

Total number of balls in the end
= 8 u + 4 u + 3 u - 13
= 15 u - 13

15 u - 13 = 32
15 u = 32 + 13
15 u = 45

1 u = 45 ÷ 15 = 3

Number of green balls in the end
= 8 u 
= 8 x 3
= 24

Answer(s): 24