There were red, brown and grey marbles in a bottle. Sean put another 5 red marbles and 4 grey marbles in the bottle, then the ratio of the number of brown marbles to the number of grey marbles became 5 : 3. Then, he doubled the number of red marbles and removed 14 grey marbles. The ratio of the number of red marbles to brown marbles became 2 : 1. He counted and found that there were a total of 148 marbles left in the bottle. Find the number of red marbles that he had at first.
|
Red marbles |
Brown marbles |
Grey marbles |
Total |
Before |
5 u - 5 |
5 u |
3 u - 4 |
|
Change 1 |
+ 5 |
|
+ 4 |
|
After 1
|
1x5 = 5 u |
5 u |
3 u |
|
Change 2
|
+ 1x5 = 5 u |
|
- 14 |
|
After 2
|
2x5 = 10 u |
1x5 = 5 u |
3 u - 14 |
148 |
The number of brown marbles remains unchanged. Make the number of brown marbles the same. LCM of 1 and 5 is 5.
Total number of marbles in the end
= 10 u + 5 u + 3 u - 14
= 18 u - 14
18 u - 14 = 148
18 u = 148 + 14
18 u = 162
1 u = 162 ÷ 18 = 9
Number of red marbles at first
= 5 u - 5
= 5 x 9 - 5
= 45 - 5
= 40
Answer(s): 40