There were green, yellow and brown marbles in a box. Sean put another 7 green marbles and 11 brown marbles in the box, then the ratio of the number of yellow marbles to the number of brown marbles became 4 : 3. Then, he doubled the number of green marbles and removed 27 brown marbles. The ratio of the number of green marbles to yellow marbles became 2 : 1. He counted and found that there were a total of 48 marbles left in the box. Find the number of green marbles that he had in the end.
|
Green marbles |
Yellow marbles |
Brown marbles |
Total |
Before |
4 u - 7 |
4 u |
3 u - 11 |
|
Change 1 |
+ 7 |
|
+ 11 |
|
After 1
|
1x4 = 4 u |
4 u |
3 u |
|
Change 2
|
+ 1x4 = 4 u |
|
- 27 |
|
After 2
|
2x4 = 8 u |
1x4 = 4 u |
3 u - 27 |
48 |
The number of yellow marbles remains unchanged. Make the number of yellow marbles the same. LCM of 1 and 4 is 4.
Total number of marbles in the end
= 8 u + 4 u + 3 u - 27
= 15 u - 27
15 u - 27 = 48
15 u = 48 + 27
15 u = 75
1 u = 75 ÷ 15 = 5
Number of green marbles in the end
= 8 u
= 8 x 5
= 40
Answer(s): 40