There were grey, red and blue beads in a container. Sean put another 10 grey beads and 2 blue beads in the container, then the ratio of the number of red beads to the number of blue beads became 5 : 3. Then, he doubled the number of grey beads and removed 17 blue beads. The ratio of the number of grey beads to red beads became 2 : 1. He counted and found that there were a total of 127 beads left in the container. Find the number of grey beads that he had in the end.

	Grey beads	Red beads	Blue beads	Total
Before	5 u - 10	5 u	3 u - 2
Change 1	+ 10		+ 2
After 1	1x5 = 5 u	5 u	3 u
Change 2	+ 1x5 = 5 u		- 17
After 2	2x5 = 10 u	1x5 = 5 u	3 u - 17	127

The number of red beads remains unchanged. Make the number of red beads the same. LCM of 1 and 5 is 5.

Total number of beads in the end
= 10 u + 5 u + 3 u - 17
= 18 u - 17

18 u - 17 = 127
18 u = 127 + 17
18 u = 144

1 u = 144 ÷ 18 = 8

Number of grey beads in the end
= 10 u 
= 10 x 8
= 80

Answer(s): 80